The correct option is A 41.5%
2Cu2++2I−⇌2Cu++I2
2Na2S2O3+I2⇌Na2S4O6+2NaI
Thus, 1molCu2+=1molNa2S2O3
Hence, total number of moles of copper in 20 ml ofsample =20×0.03271000=6.54×10−4 mol.
Hence, total number of moles of copper in 1000 ml of sample =1000×6.54×10−420=0.0327 mol.
Hence mass of copper =63.5×0.0327=2.076 g
Percentage of copper in sample =2.0765×100=41.5 %.