Question

5 girls and 5 boys can be seated around a circular table such that no 2 girls will sit together in ways

• A. 5!.4!
• B. 4!.4!
• C. 5.5!
• D. 600

Answer 1

The correct option is A 5!.4!

First arrange 5 boys around the table. This can be done in 4! ways.

Now, there are 5 gaps in the circular arrangement as shown above.

So, seating 5 girls in 5 gaps in circular table can be considered as normal permutation and number of ways they can be seated = 5!

So, total number of ways in which seating can be done = 4! $\times$ 5!