Question

5 harmonic means are inserted between 5 and 10. The common difference of corresponding A.P is.

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Let $H_1$, $H_2$,-------- $H_5$ be the HMs inserted,

$\Rightarrow$ 5, $H_1$, $H_2$, ------- $H_5$, 10 forms a H.P.

Common difference of corresponding AP

D = $\frac{a-b}{(n+1)ab}$

Here n = 5, a = 5, b = 10

So, D = $\frac{5-10}{6\times 50}$ = $\frac{-1}{60}$