Question

5. In an open organ pipe third harmonic is 450 Hz. What is the frequency of fifth harmonic.

6. A train has to negotiate a curve of 400 m. By how much should the outer rail be raised with respect to inner rail for a speed of 48 Km/hr? The distance between the rails is 1 m.

Answer 1

Dear Student,

$$\begin{gathered} \left(5\right)f=n{f}_0 \\ 450=3f_0 \\ {f}_0=150Hz \\ frequencyofthefifthharmonic=150*5=750Hz \\ \left(6\right)forsafeturn \\ \tan \theta =\frac{v^2}{rg};v=48*\frac{5}{18}=40/3m/s \\ \frac{x}{1}=\frac{{\displaystyle \frac{1600}{9}}}{400*10}=0.044m \\ soitshouldberaisedby0.044m \\ Regards \end{gathered}$$