5 ml of 0.4NNaOH is mixed with 20 ml of 0.1NHCl. The pH of the resulting solution will be:
A
6
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B
7
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C
8
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D
5
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Solution
The correct option is A7 5 ml of 0.4NNaOH is mixed with 20 ml of 0.1NHCl. The pH of the resulting solution will be 7.
Number of milligram equivalents of NaOH=5×0.4=2.
Number of milligram equivalents of HCl=20×0.1=2.
Thus, NaOH will be completely neutralised with HCl to form salt NaCl. NaCl is a salt of strong base with strong acid. Such salts do not undergo hydrolysis and give neutral aqueous solutions.