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Hydrogen Peroxide

5 mL of N H...

Question

$5 m L$ of $N H C l, 20 m L$ of $N / 2 H_{2} S O_{4}$ and $30 m L$ of $N / 3 H N O_{3}$ are mixed together and volume made to $1 L$ .

The normality of the resulting solution is :

N / 5

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N / 10

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N / 20

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N / 40

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Solution

The correct option is D $N / 40$
We know

Meq= N $\times$ V
where Meq is the equivalent molarity
N is normality of the solution
V is volume of solution

Applying the formula to each of the solution separately
1) HCl
Meq= 1 $\times$ 5 = 5M

2) H2SO4
Meq= $\frac{1}{2} \times 20 = 10$ M

3) HNO3
Meq= $\frac{1}{3} \times 30 = 10$ M

For total solution
Meq = M1 + M2 + M3
Meq = 5+10+10 = 25 M
and volume = 1000 mL

Thus applying the same formula
Meq= N $\times$ V
25 = N $\times$ 1000
N= $\dfrac{25}{1000} N
= $\frac{N}{40}$

Thus normality of the solution would be $\frac{N}{40}$ .

Hence, the correct option is $D$

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5 mL of N HCl,20 mL of N/2 H2SO4 and 30 mL of N/3 HNO3 are mixed together and volume made to 1L. The normality of the resulting solution is :

$5 m L$ of $N H C l, 20 m L$ of $N / 2 H_{2} S O_{4}$ and $30 m L$ of $N / 3 H N O_{3}$ are mixed together and volume made to $1 L$ .

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