5 moles of A, 6 moles of Z are mixed with sufficient amount of C to produce final product F. Then find the maximum moles of F which can be produced. Assuming that the product formed can also be reused. Reactions are:
A+2Z→B
B+C→Z+F
A
3 moles
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B
4.5 moles
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C
5 moles
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D
6 moles
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Solution
The correct option is C5 moles A+2Z⟶B
B+C⟶F+Z
3moles of A+6moles of Z⟶3moles of B
3moles of B+3moles of C⟶3moles of F+3moles of Z
Now, Dividing equation by 2;
1.5moles of A+3moles of Z⟶1.5moles of B
1.5moles of B+1.5moles of C⟶1.5moles of F+1.5moles of Z
Now, 1.5moles of Z are reused.
Dividing previous 2 equation by 3
0.5moles of A+1moles of Z⟶0.5moles of B
0.5moles of B+0.5moles of C⟶0.5moles of Z+0.5moles of F
Now, all of A is consumed hence no reaction, will take place.