Question

$5$ moles of an ideal gas at ${427}^o$C expands isothermally and reversibly from a volume of $6$L to $60$L. Calculate the work done in KJ.

Answer 1

Given that:

$T={427}^{0}C$

$V_f=60L$

$V_i=6L$

Hence the Work done in an isothermal reversible process is given by,

$w=nRTln\frac{V_f}{V_i}$

$\Rightarrow w=1mol\times 8.314mo{l}^{-1}{K}^{-1}\times 427K\times In\frac{60}{6}$

$\therefore w=8174.35J$

$\therefore w=8.1743KJ$