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Question

5 moles of an ideal monatomic gas undergoes adiabatic free expansion from 10 L, (e4) atm to (e) atm. The change in entropy (in Cal/K) of the system is:
[Answer as xyz, in which x = 1 if ΔS= +ve and x = 0 if ΔS= -ve and yz are representing the numerical value of ΔS

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Solution

Since the process is performed under free expansion, w=0 and ΔU=0 then it is also isothermal process. Hence,
ΔS=nR lnP1P2
ΔS=30
P1=e4
P2=e1

ΔS=5×R lne4e1
=5×R[ln e4ln e1]
=5×R×[41]
=5×2×3=30 cal
ΔS= +ve
x=1
y z
3 0

x y z
1 3 0

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