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Stoichiometric Calculations

5 moles of ...

Question

$5$ moles of $B a (O H)_{2}$ are treated with excess of $C O_{2}$ . How much $B a C O_{3}$ will be formed?

39.4

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197

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591

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985

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Solution

The correct option is D $985$ g
5 moles of barium hydroxide will react with excess of carbon dioxide to give 5 moles of barium carbonate.
The molar mass of barium carbonate is 197.4 g/mol.
Mass of barium carbonate obtained will be $5 \times 197.4 = 985 g$

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Here,will the no. of moles CO2 released is equal to the no.of moles of BaCO3??? If yes,how?

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N a H C O_{3}

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N a_{2} C O_{3} + B a (O H)_{2} \to B a C O_{3} + 2 N a O H

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N a H C O_{3}

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