5 moles of SO2 and 5 moles of O2 are allowed to react to form SO3 in a closed vessel. At the equilibrium, 60% of SO2 is used up. The total number of moles in the vessel at equilibrium is:
A
10.0
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B
8.5
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C
10.5
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D
3.9
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Solution
The correct option is D8.5
The reaction is depicted as:
SO2+12O2⟷SO3
We have initially:
SO2=5 mol
O2=5 mol
SO3=0 mol
At equilibrium :
60% SO2 is used up-
SO2 = 5−5(0.6) = 2 mol
O2=5−5(0.3) = 3.5 mol
SO3=5(0.6)=3 mol
Therefore, total moles of SO2, O2 and SO3 at equilibrium =8.5 mol