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Question

5 Nephrologists decide to hold daily meetings such that (i) At least one Nephrologist attend each day. (ii) A different set of Nephrologists must attend on different days. (iii) On day N for each 1 ≤ d < N, at least one Nephrologist must attend who was present on day d. How many maximum days can meetings be held?

A
14
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B
16
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C
20
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D
None of these
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Solution

The correct option is B 16

We need to find the largest possible number of subsets of {1, 2, 3, 4, 5} such that no 2 subsets are disjoint. Fix one element from the set to be presented in each subset and we can have 24 such possibilities.

Because one element is common. So, remaining 4 can be selected 4C0+4C1+4C2+4C3+4C4=24=16 ways. There are total 16 days.


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