$5$ out of $6$ persons who usually work in an office prefer coffee in the mid morning, the other always drink tea. This morning of the usual $6$ , only $3$ are present. The probability that one of them drinks tea is?

1 / 2

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1 / 12

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25 / 72

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5 / 72

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Solution

The correct option is A $1 / 2$
5 like coffee and 1 likes tea
Only 3 are present and it contains a guy who likes tea=1* ${5_{C}}_{2}$ =10
Total ways of presence= ${6_{C}}_{3}$ =20
Probability=10/20=1/2

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5 out of 6 persons who usually work in an office prefer coffee in the mid morning, the other always drink tea. This morning of the usual 6, only 3 are present. The probability that one of them drinks tea is?

The correct option is A 1/25 like coffee and 1 likes teaOnly 3 are present and it contains a guy who likes tea=1* 5C2=10Total ways of presence=6C3=20Probability=10/20=1/2

$5$ out of $6$ persons who usually work in an office prefer coffee in the mid morning, the other always drink tea. This morning of the usual $6$ , only $3$ are present. The probability that one of them drinks tea is?

The correct option is A $1 / 2$
5 like coffee and 1 likes tea
Only 3 are present and it contains a guy who likes tea=1* ${5_{C}}_{2}$ =10
Total ways of presence= ${6_{C}}_{3}$ =20
Probability=10/20=1/2