Question

5 particles are moving along the x-axis with different velocities. Match their velocity time graphs with corresponding acceleration time graph.

• A. p - iv, q - ii, r - i, s - iii, t - v
• B. p - v, q - ii, r - i, s - iv, t - iii
• C. p - i, q - v, r - i, s - iii, t - iv
• D. p - iv, q - ii, r - i, s - iii, t - i

Answer 1

The correct option is D p - iv, q - ii, r - i, s - iii, t - i

(p) Lets go through each graph initially at t = 0 the slope is 0

So acceleration = 0

Later we see the slope increases and is positive.As 0 is increasing So will acceleration p - iv

(q) at t = 0 slope = 0,so acceleration = 0 with time we see.But the slope is negative as angle is obtuse so acceleration is increasing in negative (q - ii)

(r) at t = 0, slope is large and positive slope is decreasing.So acceleration is decreasing and finally becomes 0.So (r - i)

(s) at t = 0 the slope is large as steeper the line higher the slope.But we also see the angle is obtuse so slope is negative.And as time progress the steepness goes on decreasing and finally it becomes 0.So t = 0 a is high and negative at t = $\alpha$ acceleration is 0.