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Equipartition Theorem

5. Relation b...

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5. Relation between Kf and Kb.( Elevation in freezing point and boiling point)

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Q. Elevation in the boiling point for 1 molal solution of glucose is 2K. The depression in the freezing point of 2 molal solutions of glucose in the same solvent is 2K. The relation between

K_{b}

K_{f}

Q. An aqueous solution freezes at -

{0.186}^{o} C

K_{f}

= {1.86}^{o} C k g m o l^{- 1}

K_{b}

= {0.512}^{o} C k g m o l^{- 1}

). What is the elevation in boiling point?

Q. For an aqueous solution, freezing point is

- {0.186}^{0} C

. Elevation of the boiling point is the same solution is : (

K_{f} = {1.86}^{0} m o l^{- 1} k g

K_{b} = {0.512}^{0} m o l^{- 1} k g

)

Q. A solution of urea in water has a boiling point of

{100.18}^{\circ} C .

Calculate the freezing point of the same solution. Molal depression and elevation constants for water

K_{f}

K_{b}

{1.86}^{\circ} C k g m o l^{- 1}

{0.512}^{\circ} C k g m o l^{- 1}

Q. For an aqueous solution freezing point is –

{0.186}^{\circ} C

. Elevation of the boiling point of the same solution is (

K_{f}

m o l e^{- 1}

K_{b}

m o l e^{- 1}

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