5 kJ of heat required to raise the temperature of 10 moles of a gas by 100- C- at a constant volume- The specific heat capacity of the gas is J - mol - K A- 5B- 25- 10D- 13-4

The correct option is A 5Given: Q = 5 kJ, Δ T = 100 K, n =10 we know that, Q = n C_v Δ T 5 × 10^3 = 10 × C_v × 100 ⇒ C_v = 5 × 10^310 × 100 = 5 J/mol K ...

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Standard XII

Physics

Specific Heat Capacity

5 kJ of heat ...

Question

$5 kJ$ of heat required to raise the temperature of $10 moles$ of a gas by $100^{\circ} C$ , at a constant volume. The specific heat capacity of the gas is $(J/ mol-K)$

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Solution

The correct option is A $5$
Given: $Q = 5 kJ, Δ T = 100 K, n = 10$
we know that, $Q = n C_{v} Δ T$
$5 \times 10^{3} = 10 \times C_{v} \times 100$
$\Rightarrow C_{v} = \frac{5 \times 10^{3}}{10 \times 100} = 5 J/mol -K$

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5 kJ of heat required to raise the temperature of 10 moles of a gas by 100∘C, at a constant volume. The specific heat capacity of the gas is (J/ mol-K)

The correct option is A 5Given: Q=5 kJ,ΔT=100 K,n=10 we know that, Q=nCvΔT 5×103=10×Cv×100 ⇒Cv=5×10310×100=5 J/mol -K

$5 kJ$ of heat required to raise the temperature of $10 moles$ of a gas by $100^{\circ} C$ , at a constant volume. The specific heat capacity of the gas is $(J/ mol-K)$

The correct option is A $5$
Given: $Q = 5 kJ, Δ T = 100 K, n = 10$
we know that, $Q = n C_{v} Δ T$
$5 \times 10^{3} = 10 \times C_{v} \times 100$
$\Rightarrow C_{v} = \frac{5 \times 10^{3}}{10 \times 100} = 5 J/mol -K$