The correct option is A 2.5 mL
Rate of diffusion for a gas(r)=Volume of gas coming outTime taken∝1√Molar mass of the gas
rH2=5 mL1 s=5 mL/s
rO2rH2=√MH2MO2=√232=14
∴rO2=rH2×14=5 mL/s×14=54 mL/s
Hence, the volume of O2 diffused in 2 seconds =54 mL/s×2 s=2.5 mL