wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

5th term from the end in the expansion of (x22−2x2)12 is

A
7920x4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7920x4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
7920x4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
7920x4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 7920x4
5th term in the expansion of(x222x2)12 is
Tr+1=nCrxr.ynr
T5=12C4[(x22)4(2x2)8]
=12!4!8!.x824.28x16
=7920x4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualising the Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon