(5−x)(6−5x)(2−x)
(5−x)(6−5x)(2−x)=[5(6−5x)−x(6−5x)](2−x)=[30−25x−6x+5x2](2−x)=(30−31x+5x2)(2−x)=2(30−31x+5x2)−x(30−31x+5x2)=60−62x+10x2−30x+31x2−5x3=60−62x−30x+10x2+31x2−5x3=60−92x+41x2−5x3
How to solve
(5-x)(6-5x)(2-x)
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