Given equation is x 2 +3x+5=0 .
Any equation of the form a x 2 +bx+c=0 has the solution
x= −b± D 2a
Here, D= b 2 −4ac is called the discriminant of the quadratic equation.
Therefore,
x= −3± 9−4×1×5 2 = −3± 11 i 2
Thus, x= −3± 11 i 2
Find the equation of circle circumscribing the quadrilateral formed by four lines 3x + 4y − 5 = 0, 4x − 3y − 5 = 0, 3x + 4y + 5 = 0 and 4x − 3y + 5 = 0
Solve graphically.
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