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Standard XII

Chemistry

Limiting Reagent or Reactant

50.0 kg of ...

Question

$50.0 k g$ of $N_{2} (g)$ and $10.0 k g$ of $H_{2} (g)$ are mixed to procedure $N H_{3} (g)$ . Calculate the $N H_{3} (g)$ formed. Identify the limiting reagent in the production of $N H_{3}$ .

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Solution

Balanced chemical equation for the above reaction :
$N_{2} + 3 H_{2} ⟶ 2 N H_{3} 28 g 6 g 34 g 28 g N_{2} ⟶ 6 g H_{2} 1 g N_{2} ⟶ \frac{6}{28} g H_{2} 50 k g N_{2} ⟶ \frac{6}{28} \times 50 k g H_{2} ⟶ 10.71 k g H_{2} ⟶ r e q u i r e d B u t H_{2} a v a i l a b l e = 10 k g ∴ H_{2} i s t h e l i m i t i n g r e a g e n t N o w, 6 g H_{2} ⟶ 34 g {N H}_{3} 1 g H_{2} ⟶ \frac{34}{6} g {N H}_{3} 10 k g H_{2} ⟶ \frac{34}{6} \times 10 k g {N H}_{3} ⟶ 56.66 k g {N H}_{3}$

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50.0 kg of N2 (g) and 10.0 kg of H2 (g) are mixed to procedure NH3 (g). Calculate the NH3 (g) formed. Identify the limiting reagent in the production of NH3.

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$50.0 k g$ of $N_{2} (g)$ and $10.0 k g$ of $H_{2} (g)$ are mixed to procedure $N H_{3} (g)$ . Calculate the $N H_{3} (g)$ formed. Identify the limiting reagent in the production of $N H_{3}$ .