50.0mL of 0.10MHCl is mixed with 50.0mL of 0.10MNaOH. The solution's temperature rises by 3.0∘C. Calculate the enthalpy of neutralization per mole of HCl. (Assuming density of sol. =1g/ml and specifice heat of water).
A
−2.5×102kJ/mole
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B
−1.3×102kJ/mole
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C
−8.4×101kJ/mole
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D
−6.3×101kJ/mole
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Solution
The correct option is A−2.5×102kJ/mole
HCl+NaOH→NaCl+H2O
Molarity=no.ofmoles(n)volume(L)
No. of moles of acid used=0.05×0.1=0.05
No. of moles of base used=0.05×0.1=0.05
So, 0.05 moles of HCl reacts with 0.05 moles of NaOH to form 0.05 moles of NaCl.