50 bells $B_{1}, B_{2}, B_{3}, . . . . . . . B_{50}$ start ringing together. The bells ring after every 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.....50 sec respectively.
In a span of 1 day , how many times do bells $B_{10}, B_{20}, . . . . B_{50}$ ring together?

142

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143

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144

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145

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Solution

The correct option is C
144

$B_{10}, B_{20}, . . . . B_{50}$ will ring together at the LCM of 10, 20 .... 50.
LCM of 10, 20, 30, 40, 50 = 600 seconds or 10 minutes. Minutes in a day = 1440. Hence the bells will ring together 144 times.

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50 bells B1,B2,B3,.......B50 start ringing together. The bells ring after every 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.....50 sec respectively. In a span of 1 day , how many times do bells B10,B20,....B50 ring together?

The correct option is C 144 B10,B20,....B50 will ring together at the LCM of 10, 20 .... 50. LCM of 10, 20, 30, 40, 50 = 600 seconds or 10 minutes. Minutes in a day = 1440. Hence the bells will ring together 144 times.

50 bells $B_{1}, B_{2}, B_{3}, . . . . . . . B_{50}$ start ringing together. The bells ring after every 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.....50 sec respectively.
In a span of 1 day , how many times do bells $B_{10}, B_{20}, . . . . B_{50}$ ring together?

The correct option is C
144

$B_{10}, B_{20}, . . . . B_{50}$ will ring together at the LCM of 10, 20 .... 50.
LCM of 10, 20, 30, 40, 50 = 600 seconds or 10 minutes. Minutes in a day = 1440. Hence the bells will ring together 144 times.