50 c.c. of air at normal pressure is compressed to 38 c.c. Taking the temperature to remain constant,find the increase of pressure.

240 mm

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420 mm

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250 mm

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650 mm

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Solution

The correct option is A 240 mm
According to Boyle’s Law
$P_{1} V_{1} = P_{2} V_{2} o r P_{1} \times 38 = 760 \times 50$
$\Rightarrow P_{1} = \frac{760 \times 50}{38} = 1000 m m$
Hence, increase in pressure = 1000 – 760 = 240 mm

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50 c.c. of air at normal pressure is compressed to 38 c.c. Taking the temperature to remain constant,find the increase of pressure.

The correct option is A 240 mmAccording to Boyle’s Law P1V1=P2V2orP1×38=760×50 ⇒P1=760×5038=1000mm Hence, increase in pressure = 1000 – 760 = 240 mm

The correct option is A 240 mm
According to Boyle’s Law
$P_{1} V_{1} = P_{2} V_{2} o r P_{1} \times 38 = 760 \times 50$
$\Rightarrow P_{1} = \frac{760 \times 50}{38} = 1000 m m$
Hence, increase in pressure = 1000 – 760 = 240 mm