50 $c m^{3}$ of 0.2 $N$ HCl is titrated against 0.1 $N$ NaOH solution. The titration is discontinued after adding 50 $c m^{3}$ of NaOH. The remaining titration is completed by adding 0.5 $N$ KOH. The volume of KOH required for completing the titration is:

12 c m^{3}

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10 c m^{3}

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25 c m^{3}

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10.5 c m^{3}

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Solution

The correct option is B $10 c m^{3}$

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