50÷5−7×2+11+3×10÷2−2+6×6=
20
36
40
56
We have to use BODMAS rule for the calculations. So,50÷5−7×2+11+3×10÷2−2+6×6=10−7×2+11+3×5−2+6×6=10−14+11+15−2+36=−4+11+15−2+36=62−6=56
The remainder obtained when (2+52+63+114+25+56+67+118+……297+598+699+11100) is divided by 5 is
2+22+23+24+25+26+27+28+29+210+211 =___