Question

$50gCaC{O}_3$ will react with ............. $g$ of $20\%HCl$ by weight.

• A. $36.5g$
• B. $73g$
• C. $109.5g$
• D. $182.5g$

Answer 1

The correct option is D $182.5g$

$CaC{O}_3$+ 2$HCl$ → $CaC{l}_2$ + $C{O}_2$+ $H_{2}O$

1 mol 2 moles

$20$ % $HCl$ contains $20g$ $HCl$ in $100$ g water

$1$ mol $CaC{O}_3$ = $100g$

$50$ g $CaC{O}_3$ = $0.5$ moles $CaC{O}_3$

$0.5$ mole $CaC{O}_3$correspond to 1 mol $HCl$

$1$ mol $HCl$= $36.5g$ $HCl$

$20$ g $HCl$ in $100g$ water

$36.5g$ $HCl$ = $182.5g$ $H_{2}O$

Hence, $182.5g$ solution of $20$ % $HCl$ is required.