50 g of a certain metal at 150- C is immersed in 100 g of water at 11- C- The final temperature is 20- C- Find the specific heat capacity of the metal- Specific heat capacity of water is 4-2 Jg -1 K -1 -A- 0-582

The correct option is A 0.582Given: Mass of metal, m_m= 50 g Mass of water, m_w nbsp;= 100 g nbsp; Temperature of metal =150^∘ C Temperature of water =11^∘ ...

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Standard X

Physics

Specific Heat Capacity

50 g of a cer...

Question

$50 g$ of a certain metal at $150^{\circ} C$ is immersed in $100 g$ of water at $11^{\circ} C$ . The final temperature is $20^{\circ} C$ . Find the specific heat capacity of the metal.
Specific heat capacity of water is $4.2 J g^{- 1} K^{- 1}$ ).
0.582

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Solution

The correct option is A 0.582
Given:
Mass of metal, $m_{m} = 50 g$
Mass of water, $m_{w} = 100 g$
Temperature of metal $= 150^{\circ} C$
Temperature of water $= 11^{\circ} C$
Temperature of the mixture $= 20^{\circ} C$
Specific heat of water, $S_{w} = 4.2 J g^{- 1} K^{- 1}$
Heat lost by the metal = Heat gained by water
$m_{m} s_{m} Δ T_{m} = - m_{w} s_{w} Δ T_{w}$
$50 \times s_{m} \times (150 - 20) = - 100 \times 4.2 \times (11 - 20$
$s_{m} = 0.582 J g^{- 1} K^{- 1}$

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50 g of a certain metal at 150∘C is immersed in 100 g of water at 11∘C. The final temperature is 20∘C. Find the specific heat capacity of the metal. Specific heat capacity of water is 4.2 Jg−1 K−1).0.582

$50 g$ of a certain metal at $150^{\circ} C$ is immersed in $100 g$ of water at $11^{\circ} C$ . The final temperature is $20^{\circ} C$ . Find the specific heat capacity of the metal.
Specific heat capacity of water is $4.2 J g^{- 1} K^{- 1}$ ).
0.582