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Question

50 g of a certain metal at 150C is immersed in 100 g of water at 11C. The final temperature is 20C. Find the specific heat capacity of the metal.
Specific heat capacity of water is 4.2 Jg1 K1).
  1. 0.582

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Solution

The correct option is A 0.582
Given:
Mass of metal, mm=50 g
Mass of water, mw=100 g
Temperature of metal =150C
Temperature of water =11C
Temperature of the mixture =20C
Specific heat of water, Sw=4.2 Jg1K1

Heat lost by the metal = Heat gained by water
mmsmΔTm=mwswΔTw
50×sm×(15020)=100×4.2×(1120
sm=0.582 Jg1K1


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