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Standard XII

Chemistry

Enthalpy of Neutralisation

50 g of a sam...

Question

$50 g$ of a sample of $N a O H$ required for complete neutralisation of $1 l i t r e N H C l$ . What is the percentage purity of $N a O H$ ?

80

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70

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60

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50

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Solution

The correct option is B $80$
for complete neutralisation we have
moles of acid = moles of base
moles of acid = normality $$ volume = $1 1$
moles of base = 1 = $\frac{g i v e n m a s s}{m o l e c u l a r m a s s}$

so, given mass = moles $$ molecular mass = 1 $$ = 40

percentage purity = $\frac{40}{50} * 100$ = 80 %

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50 g of a sample of NaOH required for complete neutralisation of 1 litre N HCl. What is the percentage purity of NaOH?

The correct option is B 80for complete neutralisation we havemoles of acid = moles of basemoles of acid = normality ∗ volume = 1∗1moles of base = 1 =givenmassmolecularmassso, given mass = moles ∗ molecular mass = 1∗ = 40percentage purity = 4050∗100 = 80 %

$50 g$ of a sample of $N a O H$ required for complete neutralisation of $1 l i t r e N H C l$ . What is the percentage purity of $N a O H$ ?