50 g of a saturated aqueous solution of potassium chloride at $30^{o} C$ is evaporated to dryness, when 13.2 g of dry KCl was obtained. Calculated the solubility of KCl in water at $30^{o} C$ .

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Solution

Mass of water in solution = (50 - 13.2) = 36.8 g
Solubility of KCl $= \frac{M a s s o f K C l}{M a s s o f w a t e r} \times 100 = \frac{13.2}{36.8} \times 100 = 35.87 g$

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50 g of a saturated aqueous solution of potassium chloride at 30oC is evaporated to dryness, when 13.2 g of dry KCl was obtained. Calculated the solubility of KCl in water at 30oC.

Mass of water in solution = (50 - 13.2) = 36.8 gSolubility of KCl =MassofKClMassofwater×100=13.236.8×100=35.87g

50 g of a saturated aqueous solution of potassium chloride at $30^{o} C$ is evaporated to dryness, when 13.2 g of dry KCl was obtained. Calculated the solubility of KCl in water at $30^{o} C$ .

Mass of water in solution = (50 - 13.2) = 36.8 g
Solubility of KCl $= \frac{M a s s o f K C l}{M a s s o f w a t e r} \times 100 = \frac{13.2}{36.8} \times 100 = 35.87 g$