$50 g$ of copper coin is heated to increase its temperature by $10^{\circ} C$ . The coin is then put in $10 g$ of water, after which it returns to its initial temperature before heating. What is the temperature change of water? (Specific heat of copper = $420 J k g^{- 1} K^{- 1}$ , specific heat of water = $4186 J k g^{- 1} K^{- 1}$

8^{\circ} C

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5^{\circ} C

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10^{\circ} C

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3^{\circ} C

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Solution

The correct option is B $5^{\circ} C$
Given:
mass of copper coin, $m_{c} = 50 g = 0.05 k g$ .
Temperature change of copper coin, $Δ T_{c} = 10^{\circ} C$ .
Specific heat of copper, $S_{c} = 420 J k g^{- 1} K^{- 1}$ .
Mass of water, $m_{w} = 10 g = 0.01 k g$ .
Specific heat of water, $S_{w} = 4186 J k g^{- 1} K^{- 1}$ .
Let the temperature change of water = $Δ T_{w}$

Heat lost = Heat gained

$m_{c} \times S_{c} \times Δ T = m_{w} \times S_{w} \times Δ T_{w}$
$\Rightarrow 0.05 \times 420 \times 10 = 0.01 \times 4186 \times Δ T_{w}$
$\Rightarrow 210 = 41.86 \times Δ T_{w}$
$\Rightarrow Δ T_{w} = {\frac{210}{41.86}}^{\circ} C$
$\Rightarrow Δ T_{w} = 5^{\circ} C$

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50 g

of copper is heated to increase its temperature by

10^{\circ} C

. If the same quantity of heat is given to

10 g

of water, then the rise in its temperature (in

^{\circ} C

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(Specific heat of copper

= 420 J k g^{- 1} K^{- 1}

,
Specific heat of water

= 4186 J k g^{- 1} K^{- 1}

)

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, what will be the rise in its temperature? Assume no state change.
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Specific heat of water $= 4200 J k g^{- 1 \circ} C$

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, the rise in its temperature is (specific heat of copper = $420 J / k g /^{\circ} C$ , specific heat of water = $4200 J / k g /^{\circ} C$ )

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, then the rise in its temperature is (specific heat of copper $= 420 J / k g /^{\circ} C$ )

Q. 50 g of copper is heated to increase its temperature by

10^{\circ} C .

If the same quantity of heat is given to 10 g of water, the rise in its temperature is:
Specific heat of copper is

420 J k g^{- 1}^{\circ} C

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