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Question

50 g of copper is heated to increase its temperature by 10C. If the same quantity of heat is given to 10 g of water, what will be the rise in its temperature? Assume no state change.
Specific heat of copper =420 J kg1 C
Specific heat of water =4200 J kg1 C


A

5C

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B

6C

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C

7C

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D

8C

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Solution

The correct option is A

5C


Same amount of heat is supplied to copper and water.

mcccΔTc = mωcωΔTω
where
mc: Mass of copper
mw: Mass of water,
cc: Specific heat of copper
cw: Specific heat of water
ΔTc: Temperature difference of copper
ΔTw: Temperature difference of water

ΔTw=mcccΔTcmwcw
ΔTw=50×103×420×1010×103× 4200
ΔTw=5C

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