wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

50g of copper is heated to increase its temperature by 10C. If the same quantity of heat is given to 10g of water, then what would be the rise in its temperature?
(specific heat of copper =420J/kg/C, specific heat of water =4200J/kg/C)


A

5C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

6C

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

7C

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

8C

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

5C


Given,
Mass of copper, mc=50g
Rise in temperature, ΔTc=10C
Mass of water, mω=10g

Same amount of heat is supplied to copper and water, so
mcccΔTc = mωcωΔTω
where, m, c and ΔT is the mass, specific heat and change in temperature of copper and water respectively.

or, (ΔT)ω=mcccΔTcmωcω
=50×103×420×1010×103×4200
=5C


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Calorimeter Tackle
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon