Question

50 g of copper is heated to increase its temperature by ${10}^{\circ }C.$ If the same quantity of heat is given to 10 g of water, the rise in its temperature is:
Specific heat of copper is $420Jk{g}^{-1}{}^{\circ }C$.

• A. $5^{\circ }C$
• B. $6^{\circ }C$
• C. $7^{\circ }C$
• D. $8^{\circ }C$

Answer 1

The correct option is A $5^{\circ }C$

Same amount of heat is supplied to copper and water.
$m_c{c}_c\Delta T_c=m_w{c}_w\Delta T_w$
$\Delta T_w=\frac{m_c{c}_c\Delta T_c}{m_w{c}_w}$
$\Delta T_w=\frac{50\times {10}^{-3}\times 420\times 10}{10\times {10}^{-3}\times 4200}$
$\Delta T_w=5^{\circ }C$