$50$ g of copper is heated to increase its temperature by $10^{o}$ C. If the same quantity of heat is given to $10$ gm of water, the rise in temperature is (specific heat of copper $= 420$ J $k g^{- 1} K^{- 1}$ , specific heat of water $= 4200$ J $k g^{- 1} K^{- 1}$ ).

5^{o}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $5^{o}$ C
Heat given to copper = $(0.050 \times 450 \times 10) J$
Now, let $△ T$ be rise in temperature of water
$\Rightarrow 0.050 \times 420 \times 10 = 0.010 \times 4200 \times △ T \Rightarrow △ T = 5$

Suggest Corrections

Similar questions

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, then what would be the rise in its temperature?
(specific heat of copper $= 420 J / k g /^{\circ} C$ , specific heat of water $= 4200 J / k g /^{\circ} C$ )

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, the rise in its temperature is (specific heat of copper = $420 J / k g /^{\circ} C$ , specific heat of water = $4200 J / k g /^{\circ} C$ )

Q. 50 g of copper is heated to increase its temperature by

10^{o} C

. If the same quantity of heat is given to 10 g of water, the rise in temperature is

(s p e c i f i c h e a t o f c o p p e r = 420 J k g^{- 1} K^{- 1}, s p e c i f i c h e a t o f w a t e r = 4200 J k g^{- 1} K^{- 1})

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, what will be the rise in its temperature? Assume no state change.
Specific heat of copper $= 420 J k g^{- 1 \circ} C$
Specific heat of water $= 4200 J k g^{- 1 \circ} C$

$400 g$ of iron is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $200 g$ of water, the rise in its temperature is ___ $^{\circ} C$ (specific heat of iron = $420 J / k g /^{\circ} C$ , specific heat of water = $4200 J / k g /^{\circ} C$ )

Join BYJU'S Learning Program

50g of copper is heated to increase its temperature by 10oC. If the same quantity of heat is given to 10gm of water, the rise in temperature is (specific heat of copper=420J kg−1K−1, specific heat of water =4200J kg−1K−1).

The correct option is A 5oCHeat given to copper = (0.050×450×10)JNow, let △T be rise in temperature of water⇒0.050×420×10=0.010×4200×△T⇒△T=5

$50$ g of copper is heated to increase its temperature by $10^{o}$ C. If the same quantity of heat is given to $10$ gm of water, the rise in temperature is (specific heat of copper $= 420$ J $k g^{- 1} K^{- 1}$ , specific heat of water $= 4200$ J $k g^{- 1} K^{- 1}$ ).

The correct option is A $5^{o}$ C
Heat given to copper = $(0.050 \times 450 \times 10) J$
Now, let $△ T$ be rise in temperature of water
$\Rightarrow 0.050 \times 420 \times 10 = 0.010 \times 4200 \times △ T \Rightarrow △ T = 5$