Question

$50g$ of ice at 0 C mixed with $50g$ of water at 20 C. The final temperature of the mixture would be:

• A. -30 C
• B. -10 C
• C. 0 C
• D. 10 C

Answer 1

The correct option is C 0 C

$heatgain\left(ice\right)=heatloss\left(water\right)$

$M_i{L}_{ice}+M_i{S}_w(T-0)=M_w{S}_w(20-T)$

$50\times 20+50\times 1(T-0)=50\times 1(20-T)$

$1000+50T=1000-50T$

$T=0^{\theta }C$