Ca(OH)2+2HCl→CaCl2+2H2O and NaOH+HCl→NaCl+H2O
meqv. of HCl in 50 ml of 0.5 N HCl solution= 25 meqv.
meqv. of NaOH in 20 ml of 0.25 N NaOH solution= 5.0 meqv.
So, meqv. of HCl used to react Ca(OH)2=25−5=20 meqv.
So. meqv. of Ca(OH)2=20 meqv
So, mmol. of Ca(OH)2=202=10 mmol
So, mass of Ca(OH)2 in sample =10×74 mg=740 mg
So, % purity of Ca(OH)2 in sample =0.74050×100=1.48%