$50$ g of saturated aqueous solution of potassium chloride at $30^{o}$ C is evaporated to dryness. When $13.2$ g of dry $K C l$ was obtained. The solubility of $K C l$ in water at $30^{o}$ C is:

35.87

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25.62

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28.97

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27.81

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Solution

The correct option is A $35.87$ g
The solubility of a solute in a solvent at any temperature is defined as the maximum amount of the solute in grams which can dissolve in $100$ g of the solvent to form the saturated solution at that particular temperature.

Weight of solute $(K C l)$ $= 13.2 g$

Weight of solvent $= 50 - 13.2 = 36.8 g$

$∴$ Solubility of $K C l$ $= \frac{13.2}{36.3} \times 100 = 35.869$ .

Option A is correct.

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50g of saturated aqueous solution of potassium chloride at 30oC is evaporated to dryness. When 13.2g of dry KCl was obtained. The solubility of KCl in water at 30oC is:

$50$ g of saturated aqueous solution of potassium chloride at $30^{o}$ C is evaporated to dryness. When $13.2$ g of dry $K C l$ was obtained. The solubility of $K C l$ in water at $30^{o}$ C is: