Question

50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 m${}^3$, then the rise in the water level in the tank will be:

• A. 25 cm
• B. 35 cm
• C. 50 cm
• D. 56 cm

Answer 1

The correct option is A

25 cm

Total volume of water displaced = (4 $\times$ 50) m${}^3$ = 200 m${}^3$

$\therefore$Rise in water level =$\left(\frac{200}{40\times 20}\right)$ m = 0.25 m = 25 cm