50 mL of 0.1 M HCl and 50 mL of 2.0 M NaOH are mixed. The pH of the resulting solution is -
Consider log(2)=0.30
A
1.3
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B
4.2
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C
12.7
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D
11.7
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Solution
The correct option is C 12.7 Millimoles of HCl=0.1×50=5 mmol Millimoles of NaOH=0.2×50=10 mmol 1 mmol of HCl is neutralized by 1 mmol of NaOH ∴ Resulting solution contains 5 mmol of NaOH in (50 + 50) = 100 mL of solution ∴[OH]−=5×10−3100×10−3=5×10−2M [OH]−=5×10−2M