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Byju's Answer

Standard XII

Chemistry

Equivalent Mass

50 ml of 0....

Question

$50$ ml of $0.2$ N $K_{2} C r_{2} O_{7}$ is required to oxidize $40$ ml of $F e S O_{4}$ solution in an acidic medium.
The weight of iron present in $1 L$ of $F e S O_{4}$ solution is (atomic weight of iron is $56$ ):

14 g

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1.4 g

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140 g

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28 g

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Solution

The correct option is B $14 g$
The valency factor for $K_{2} C r_{2} O_{7}$ is 6.

$N_{1} V_{1} = N_{2} V_{2}$

$⟹ 0.2 \times 50 = N_{2} \times 40$

$⟹ N_{2} = \frac{10}{40} = \frac{1}{4}$

$⟹ N_{2} = \frac{w}{(M . w t)} \times e q . f a c t o r \times \frac{1}{V (l i t)}$

$⟹ \frac{1}{4} = \frac{w}{56} \times 1 \times 1$

$⟹ w = \frac{56}{4}$

$⟹ w = 14 g$

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Similar questions

Q. 50 mL aqueous solution of

F e S O_{4}

required 12 mL of 0.2 M

K M n O_{4}

in acidic medium for complete oxidation. Calculate the molarity of ferrous sulphate solution. The reaction is:

M n O_{4}^{-} + 5 F e^{2 +} + 8 H^{+} \to M n^{2 +} + 5 F e^{3 +} + 4 H_{2} O

Q. A

8 g m

sample of iron are containing

V %

(by wt) of iron

F e^{2 +}

was present in

1 L

solution. This solution required

V m L

of a

K M n O_{4}

solution for oxidation of

F e^{2 +}

in acidic medium. If in another titration

20 m L

of same

K M n O_{4}

is required, for oxidation of

20 m L H_{2} O_{2}

in acidic medium. Find volume strength of

H_{2} O_{2}

3

moles of a mixture of

F e S O_{4}

and

F e_{2} (S O_{4})_{3}

required

100

mL of

2

K M n O_{4}

solution in acidic medium. Hence, mole fraction of

F e S O_{4}

in the mixture is:

Q. How many grams of

K_{2} C r_{2} O_{7}

is required to oxidise

12.41

g of

F e S O_{4}

F e_{2} (S O_{4})_{3}

in an acidic medium?

(K_{2} C r_{2} O_{7} = 294; F e S O_{4} = 152)

Q. The weight of

K M n O_{4}

required to completely oxidise

0.25

moles of

F e S O_{4}

in acidic medium is:

[Molecular weight of

K M n O_{4} = 158

]

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50 ml of 0.2 N K2Cr2O7 is required to oxidize 40 ml of FeSO4 solution in an acidic medium. The weight of iron present in 1L of FeSO4 solution is (atomic weight of iron is 56):

The correct option is B 14gThe valency factor for K2Cr2O7 is 6.N1V1=N2V2⟹0.2×50=N2×40⟹N2=1040=14⟹N2=w(M.wt)×eq.factor×1V(lit)⟹14=w56×1×1⟹w=564⟹w=14g

$50$ ml of $0.2$ N $K_{2} C r_{2} O_{7}$ is required to oxidize $40$ ml of $F e S O_{4}$ solution in an acidic medium.
The weight of iron present in $1 L$ of $F e S O_{4}$ solution is (atomic weight of iron is $56$ ):