Question

50 ml of 1 M oxalic acid is shaken with 0.5 gm of wood charcoal. The final concentration of the solution after adsorption is 0.2 M. Amount of oxalic acid absorbed per gm of charcoal is (Use molar mass of hydrated oxalic acid = 126)

• A. 2.52 gm
• B. 6.30 gm
• C. 10.08 gm
• D. None

Answer 1

The correct option is C 10.08 gm

Initially weight of oxalic acid present = $W=\frac{126\times 1\times 50}{1000}=6.3gm$
Finally weight of oxalic acid remaining = $W=\frac{126\times 0.2\times 50}{1000}=\frac{6.3}{5}gm$
0.5 gm of charcoal adsorbed $6.3\times (1-\frac{1}{5})=6.3\times (\frac{45}{)}$ gm of oxalic acid
So, amount of oxalic acid adsorbed per gram of charcoal $=2\times (6.3\times (\frac{4}{5}))=10.08$ gm