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Concentration Terms - An Introduction (w/w etc)

50 mL of 20.8...

Question

50 mL of 20.8% (w/v) $B a C l_{2} (a q)$ and 100 mL of 9.8% (w/v) $H_{2} S O_{4}$ solutions are mixed. Find the mass the $B a S O_{4}$ formed.
(Molar mass of Ba = 137 g/mL)

23.32 g

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2.06 g

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0.126 g

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11.65 g

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Solution

The correct option is D 11.65 g
$B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + 2 H C l$
Mass of $B a C l_{2} = \frac{20.8}{100} \times 50 m L$
=10.4 g
moles of $B a C l_{2} = \frac{10.4}{208} = 0.05 m o l$
Mass of $H_{2} S O_{4} = \frac{9.8}{100} \times 100 = 9.8 g$
Moles of $H_{2} S O_{4} = \frac{9.8}{98} = 0.1 m o l$
Therefore, $B a C l_{2}$ is the limiting reagent.
Moles of $B a S O_{4}$ formed is 0.05 mol
Mass of $B a S O_{4}$ formed = 0.05 x 233 g
= 11.65 g
Therefore, the mass of $B a S O_{4}$ formed is 11.65 g.

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Similar questions

50 m l

solution of

B a C l_{2}

(20.8 % w/v) and

100 m l

solution of

H_{2} S O_{4}

(9.8 %w/v) are mixed then maximum mass of

B a S O_{4}

formed is:

[B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + 2 H C l]

Q. 50 ml of 20.8% (w/V)

B a C l_{2}

(aq) and 100 ml of 9.8% (w/V)

H_{2} S O_{4}

(aq) solutions are mixed. Molarity of

C l^{-}

ions in the resulting solution is : (At mass of Ba =137)

Q. 50 mL solution of

{BaCl}_{2}

(20.8% w/v) and 100 mL solution of

H_{2} {SO}_{4}

(9.8% w/v) are mixed then maximum mass of

{BaSO}_{4}

formed is:

[{BaCl}_{2} {+ H}_{2} {SO}_{4} \to {BaSO}_{4} + 2HCl]

Q. If 100 ml of

1 M H_{2} S O_{4}

solution is mixed with 100 ml of

9.8 %

(w/w)

H_{2} S O_{4}

solution (

d = 1 g / m l

) then:

Q. The amount of

B a S O_{4}

formed upon mixing

100

mL of

20.8 %

B a C l_{2}

solution with

50

mL of

9.8 %

H_{2} S O_{4}

solution will be:
[Ba

= 137

, Cl

= 35.5

, S

= 32

, H

= 1

and O

= 16

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Concentration Terms - An Introduction (w/w etc)

Standard XII Chemistry

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50 mL of 20.8% (w/v) BaCl2(aq) and 100 mL of 9.8% (w/v) H2SO4 solutions are mixed. Find the mass the BaSO4 formed. (Molar mass of Ba = 137 g/mL)

50 mL of 20.8% (w/v) $B a C l_{2} (a q)$ and 100 mL of 9.8% (w/v) $H_{2} S O_{4}$ solutions are mixed. Find the mass the $B a S O_{4}$ formed.
(Molar mass of Ba = 137 g/mL)