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pH of a Solution

50 ml of 2N a...

Question

50 ml of 2N acetic acid mixed with 10 ml of 1N sodium acetate solution will have an approximate $p H$ ( $K_{a} = 10^{- 5}$ ):

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Solution

The correct option is A 4
According to given data:

Equivalent moles of acetic acid $= 0.05 \times 2 = 0.1$

Equivalent moles of sodium acetate $= 0.01 \times 1 = 0.01$

$∴ p H = p K_{a} + log \frac{[s a l t]}{[A c i d]}$ ; $p K_{a} = - l o g K_{a} = - l o g 10^{- 5} = 5$

$p H = 5 + log \frac{0.01}{0.1}$

$p H = 5 + log (0.1)$

$\Rightarrow p H = 4$ .

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50 ml of 2N acetic acid mixed with 10 ml of 1N sodium acetate solution will have an approximate pH (Ka=10−5):

The correct option is A 4According to given data:Equivalent moles of acetic acid =0.05×2=0.1Equivalent moles of sodium acetate =0.01×1=0.01∴pH=pKa+log[salt][Acid]; pKa=−logKa=−log10−5=5pH=5+log0.010.1pH=5+log(0.1)⇒pH=4 .

50 ml of 2N acetic acid mixed with 10 ml of 1N sodium acetate solution will have an approximate $p H$ ( $K_{a} = 10^{- 5}$ ):