$50$ ml of $50 %$ alcohol solution is added to $100$ mL of water. Now the concentration of the alcohol solution becomes.

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Solution

$50$ % alcohol solution $=$ $50$ gm alcohol dissolved in $100$ ml of water.
now if we add $100$ ml of water, then final concentration will be $= (\frac{50 / 2}{50 + 100}) \times 100$ % $= 16.67$ %

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50ml of 50% alcohol solution is added to 100mL of water. Now the concentration of the alcohol solution becomes.

50% alcohol solution = 50gm alcohol dissolved in 100 ml of water.now if we add 100 ml of water, then final concentration will be =(50/250+100)×100% =16.67%

$50$ ml of $50 %$ alcohol solution is added to $100$ mL of water. Now the concentration of the alcohol solution becomes.

$50$ % alcohol solution $=$ $50$ gm alcohol dissolved in $100$ ml of water.
now if we add $100$ ml of water, then final concentration will be $= (\frac{50 / 2}{50 + 100}) \times 100$ % $= 16.67$ %