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Sigma Bond and Pi Bond

50 mL of a mi...

Question

$50$ mL of a mixture of $C O$ and $C H_{4}$ was exploded with $85$ mL of $O_{2}$ . The volume of $C O_{2}$ produced was $50$ mL. Calculate the percentage composition of the gaseous mixture:

A

C O = 20

%,

C H_{4} = 80

%

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B

C O = 80

%,

C H_{4} = 20

%

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C

C O = 40

%,

C H_{4} = 60

%

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D

C O = 60

%,

C H_{4} = 40

%

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Solution

The correct option is A $C O = 20$ %, $C H_{4} = 80$ %
Let, the volume of $C O = x$ mL
Then, volume of $C H_{4} = (50 - x)$ mL
$\begin{matrix} C O & + & \frac{1}{2} O_{2} & ⟶ & C O_{2} x m L & \frac{x}{2} m L & x m L \end{matrix}$ ...(i)

$\begin{matrix} C H_{4} & + & 2 O_{2} & ⟶ & C O_{2} & + & 2 H_{2} O (50 - x) m L & 2 (50 - x) m L & (50 - x) m L & - \end{matrix}$ ...(ii)
Total volume of $O_{2} = \frac{x}{2} + 2 (50 - x) = 85 m L$
$∴ x = 10$ mL
Volume of $C O$ = $10$ mL
Volume of $C H_{4}$ = $(50 - 10) = 40$ mL
Percentage of $C O$ = $\frac{10 \times 100}{100} = 20 %$
Percentage of $C H_{4}$ = $(100 - 20) = 80 %$

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