MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Types of Redox Reactions

50 mL of a so...

Question

$50$ mL of a solution containing $1$ g each of ${N a}_{2} C O_{3}$ , $N a H C O_{3}$ and $N a O H$ was titrated with $1 N H C l$ . The titre readings (in mL), if only methyl orange is used as an indicator from the beginning, will be $(20 + x)$ . Find the value of $x$ (as nearest integer).

Open in App

Solution

The end point using methyl orange when $1$ end point using phenolphthalein has already been detected, consumes half Meq. of ${N a}_{2} C O_{3}$ and complete $N a H C O_{3}$ .
$\frac{1}{2}$ Meq. of ${N a}_{2} C O_{3}$ +Meq. of $N a H C O_{3} =$ Meq. of $H C l$
$\frac{1}{2} \times \frac{1}{53} \times 1000 + \frac{1}{84} \times 1000 = 1 \times V_{3}$
$V_{3} = 21.3 m L$
So, nearest integer is $21$ .

Suggest Corrections

thumbs-up

0

Similar questions

20 mL

0.1 M

solution of compound

N a_{2} C O_{3} \cdot N a H C O_{3} \cdot 2 H_{2} O

is titrated against

0.05 M H C l

x mL

H C l

is used when phenolphthalein is used as an indicator and

y mL

H C l

is used when methyl orange is the indicator in two separate titrations. Hence

(y - x)

Q. Solution "X" contains

{N a}_{2} {C O}_{3}

N a H C O_{3}

. 20 ml of X when titrated using methyl orange indicator consumed 60 ml of 0.1 M

H C l

solution. In another experiment , 20 ml of X solution when titarted using phenolphthalein consumed 20 ml of 0.1 M

H C l

solution. The concentrations (in

m o l {l i t}^{- 1}

{N a}_{2} {C O}_{3}

N a H C O_{3}

in X are respectively :

Q. A solution contains

N a_{2} C O_{3}

N a H C O_{3}

10 mL

of this solution required

2.5 mL

0.1 M H_{2} S O_{4}

for neutralization using phenolphthalein as an indicator. Methyl orange is then added when a further

2.5 mL

0.2 M H_{2} S O_{4}

was required. The amount of

N a_{2} C O_{3}

N a H C O_{3}

respectively, in 1 litre of solution is:

0.6234

g sample that might contain

N a O H, N a_{2} C O_{3}, N a H C O_{3}

or a mixture of

N a O H + N a_{2} C O_{3}

N a_{2} C O_{3} + N a H C O_{3}

is titrated with

0.1062 M H C l

by two-indicator method. It is found that

40.38

mL of the acid is required to reach the phenolphthalein end-point. Methyl orange is then added to the solution and the titration continued using an additional

12.83

mL of the acid. Thus, the sample contained :

0.4 g

N a O H

N a_{2} C O_{3}

and some inert impurities were first titrated with

\frac{N}{10} H C l

using phenolphthalein as an indicator.

17.5 m L

H C l

was required at the end point. After this methyl orange was added and titrated.

1.5 m L

H C l

was required for the next end point. The weight percentage of

N a_{2} C O_{3}

in the mixture is ______. (Rounded off to the nearest integer)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Types of Redox Reactions

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Types of Redox Reactions

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon