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Salt of Weak Acid and Strong Base

50 mL of a so...

Question

$50$ mL of a solution containing $1$ g each of ${N a}_{2} C O_{3}$ , $N a H C O_{3}$ and $N a O H$ was titrated with $1 N H C l$ . The titre readings (in ml), if only methyl orange is used as an indicator from the beginning, will be $(50 + x) .$ Find the value of $x$ (as nearest integer).

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Solution

The end point using methyl orange from the beginning uses all the equivalents of bases taken.
$∴$ Meq. of $N a O H +$ Meq. of ${N a}_{2} C O_{3} +$ Meq. of $N a H C O_{3}$ $=$ Meq. of $H C l$
$\frac{1}{40} \times 1000 + \frac{1}{53} \times 1000 + \frac{1}{84} \times 1000 = 1 \times V_{2}$
$V_{2} = 55.8$ mL
So, nearest integer is $56 = 50 + 6$ .

So, the value of $x$ is 6

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20 mL

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N a_{2} C O_{3} \cdot N a H C O_{3} \cdot 2 H_{2} O

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N a H C O_{3}

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N a_{2} C O_{3}

0.5 M 10 mL H C l

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Q. A solution contains

N a_{2} C O_{3}

N a H C O_{3}

10 mL

of this solution required

2.5 mL

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2.5 mL

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was required. The amount of

N a_{2} C O_{3}

N a H C O_{3}

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0.6234

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N a O H, N a_{2} C O_{3}, N a H C O_{3}

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N a O H + N a_{2} C O_{3}

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