$50 m L$ of hydrogen diffuses out through a small hole from a vessel in $20$ minutes. The time needed for $40 m L$ of oxygen to diffuse out is:

12 m i n

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64 m i n

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8 m i n

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32 m i n

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Solution

The correct option is D $64 m i n$
$R a t e (H_{2}) = \frac{50}{20} = 2.5$

${R a t e (O}_{2}) = \frac{40}{t}$

$\frac{r_{H_{2}}}{r_{O_{2}}} = \frac{2.5}{40 / t} = \sqrt{({M_{O}}_{2} / {M_{H}}_{2})} = \sqrt{(32 / 2)} = 4$

$\Rightarrow 2.5 t = 160$

$t = 64 m i n$

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