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Concentration Terms

50 ml of mixt...

Question

$50 m l$ of mixture of $N H_{3}$ and $H_{2}$ are decomposed to yield $N_{2}$ and $H_{2}$ and to the resulting mixture $40 m l O_{2}$ is added and the mixture is sparked to yield $H_{2} O$ . When the resulting mixture of gases were passed through alkaline pyrogallol $6 m l$ contraction was observed. Calculate the percentage composition of $N H_{3}$ in the original mixture.

A

85 %

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B

72 %

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C

65 %

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D

90 %

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Solution

The correct option is A $72 %$
Let volume of $N H_{3}$ be $x$ & Hydrogen gas be $50 - x$
$2 N H_{3} ⇌ 2 N_{2} + 3 H_{2}$
After decomposition, we get $x$ ml of $N_{2}$ and $3 x / 2$ ml of $H_{2}$ .
So, Total volume= $50 - x + \frac{3}{2} x = 50 + x / 2$
Now, $40$ ml of $O_{2}$ is added, $2 H_{2} + O_{2} ⟶ 2 H_{2} O$
Reduction in volume is equal to that of $O_{2}$
$15 - V / 4 = 6 m l \Rightarrow V = 36 m l$
Hence, Percentage= $\frac{36}{50} \times 100 = 72$ %

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